select NAME, rank, count, surname_entries.id 'wiki_id' from surnames left join surname_entries on surname_entries.surname = surnames.name and surname_entries.entry_type = 1 where index2 = 'KS' order by rank asc limit 0,100 Surnames > K > KS > %22

Surnames > K > KS > %22

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
KA KE KF KH KI KJ KL KM KN KO KP KR KS KU KV KW KY
KSH KSI KSO

Full Surname List Starting with %22(Alphabetical)